GPC (Dunwoody, Dr. Kim) Calculator & Model # ___________________
R=8.3145J/(K.mol); 1cal=4.184J; 1mi=1.609km; 1yd=0.9144m;
1gal=3.785L; 1lb=453.6g;
1atm=101,325Pa; d(water)=0.997g/mL; d(Hg)=13.6g/mL; NA=6.022x1023/mol;
c=2.9979x108m/s;
1amu = 1.66x10-27kg; e=1.602x10-19C; G=6.6726x10-11Nm2/kg2;
k=8.9876x109J.m/C2.
2. Size of colloidal particles is in a range of (a) 1mm-1µm,
(b) 1 µm-1nm;
Colloidal solution shows (c) Tyndall, (d) Joule-Thomson Effect.
A(a,c), B(a,d), C(b,c), D(b,d).
3. Which one is related to a coagulation of colloidal particles?
A(Absorption of H2O by roots),
B(Food preservation with salts), C(Desalination of brackish water),
D(Curdling of milk).
4. Which ionic substance is most effective in coagulating clay particles
with negative surface
charges in a colloidal muddy water? (A)KCl, (B) CaCl2,
(C)Al2(SO4)3, (D)Na3PO4.
5. The formula of a common soap, sodium stearate, is a(C7H15COONa),
b(C17H35COONa).
In a cleaning action, the (c) hydrophobic tail, (d) hydrophillic
head of soap molecules binds to oily dirts to take it off from fabrics.
A(a,c), B(a,d), C(b,c), D(b,d).
6. A(Hydrophobic tail), B(Hydrophillic head) of a soap molecule(or ion) will bind to water molecules.
7. Soap lowers surface tension of water by (a) strengthening, (b) disrupting, hydrogen-bonds among H2O with their (c) polar heads, (d) hydrocarbon tails. A(a,c), B(a,d), C(b,c), D(b,d).
*
*
*
*
*
8. Reaction rates depends on (A)Concentration of reactants, (B)Concentration
of catalyst, (C)Temperature, (D)Surface areas of reactant/catalyst, (E)All
of these.
9. Rate constant increases with (A) collision frequency, (B) fraction of collisions having energy greater than activation energy(Ea), (C) fraction of collisions with proper orientation, (D) all of these.
10. A catalyst will (a) increase, (b) decrease, an activation energy
of a reaction
to make the reaction occur (c) slowly, (d) faster. A(a,c), B(a,d),
C(b,c), D(b,d).
*
*
*
*
*
Given the reaction, 2N2O5
-> 4NO + O2, with an initial N2O5
concentration of 0.0165M.
11. Calculate an average reaction rate during the following time interval. [N2O5] are 0.0124M at t=600s & 0.0093M at t=1,200s. A(2x105s/M), B(2x10-5M/s), C(5x10-6s/M), D(5x10-6M/s), E(-).
12. This decomposition reaction is a first-order reaction
with a rate constant k=4.8x10-4s-1 at 45oC.
The half-life(t1/2) must be A(1.5),
B(3), C(6), D(12), E(24) min.
13. Predict a concentration of N2O5 left after
1.5 hour.
A(0.011), B(0.010), C(0.0010),
D(0.0011), E(0.0012)M.
14. The time at which the concentration of N2O5
equals to that of O2 is ca.
A(40), B(50), C(60),
D(70), E(80) min.
15. How long does it take for the concentration of N2O5
to
decrease to 10% of the original concentration?
A(75), B(80), C(85),
D(90), E(95) min.
* * * * *
16. The half-life (t1/2) of first-order reaction is (A) directly, (B) inversely, (C) exponentially proportional to, (D) independent of, the reactant concentration.
17. A first-order reaction will yield a straight line in a
plot of A([A] vs. t), B([A]-1 vs. t-1),
C([A]-1 vs. t), D(ln[A] vs. t), E(ln[A]
vs.
t-1) where [A] is a reactant concentration at time t.
18. In the two-step mechanism of a reaction:
NO2(A) + NO2 -> NO3(B) + NO(C)
NO3 + CO(D) -> NO2 + CO2(E) Which one is an intermediate?
19. Decomposition of an ozone excited by a UV radiation from the
Sun: O3* ->
O2 + O
in the stratosphere is (A)Uni-, (B)Bi-,
(C)Ter-molecular reaction.
20. The automobile catalytic converter contains (A) Pt, (B)Fe, (C) NO, (D)Zn, catalyst.
* * * * *
21. Decomposition of NO2: NO2(g) -> 2NO(g)+O2(g) follows a second-order rate law, (k=0.775s/M). The reaction started with 2.00M NO2 . What is the half-life, t1/2, of this reaction? A(0.918), B(0.918), C(918), D(0.645), E(645)s.
22. Concentration of the reactant leftn after 1min above is ca. A(1), B(0.2), C(0.02), D(0.002) M.
23. According to the collision theory, reaction rate approximately
doubles for every temperature increases of 10oC. It takes about
8 min to cook an average carrot in a normal boiling water of 100
oC.
How long does it take if it is done in a pressure cooker is 120oC
?
(A) 30 sec, (B) 1min, (C) 2min, (D) 6min, (E) 8 min.
*
*
*
*
*
Chlorine dioxide, ClO2, is a reddish-yellow gas that is soluble in water, in basic solution it gives ClO3- and ClO2- ions:
2ClO2 (aq) + 2OH-(aq) -> ClO3- (aq) + ClO2- (aq) + H2O
To obtain the rate law for this reaction, the following three experiments
were run and, for each, the initial rate of reaction of ClO2
was determined.
| Initial Concentration(mol/L)
ClO2 |
Initial Concentration(mol/L)
OH- |
Initial Rate
(mol/((L s)) |
|||
| Exp. 1 | 0.060 | 0.030 | 0.0248 | ||
| Exp. 2 | 0.020 | 0.030 | 0.00276 | ||
| Exp. 3 | 0.020 | 0.090 | 0.00828 | ||
| Exp. 4 | 0.040 | 0.060 | ? |
24. What is the reaction order with respect to ClO2 ?
A(Zeroth-order), B(First-order), C(Second-order), D(Third-order),
E(Fourth-order)
25. What is the reaction order with respect to OH- ?
A(Zeroth-order), B(First-order), C(Second-order), D(Third-order),
E(Fourth-order)
26. What is the overall reaction order ?
A(Zeroth-order), B(First-order), C(Second-order), D(Third-order),
E(Fourth-order)
27. What is the rate law equation for the reaction ?
Rate =
A( k[ClO2][OH-] ), B( k[ClO2]2[OH-]
), C( k[ClO2][OH-]2), D( k[ClO2]2[OH-]2
) , E( k[ClO2] )
28. Find the value of the rate constant, k.
A(4.6), B(153), C(230), D(3890), E(7670) M-2 s-1.
29. Predict an initial rate for the Experiment #4.
A(0.00133), B(0.00414), C(0.00828), D(0.0221), E(0.0331),
F(0.552) mol/(L s).
I. Write down the chemical formula for a typical soap molecule (Sodium Stearate). Explain the cleansing action of soap using such key terms as polar, non-polar, hydrophilic, hydrophobic, and micelle.
II. Compare a first-order reaction with a second-order one. Explain with rate equations, graphs and examples. How can you distinguish experimentally a first-order from a second-order reaction?
III. Explain the three factors that determine the rate constant(k): k=pfZ.
IV. Rate constants(k) for above reaction, H2(g)+I2(g)
-> 2HI(g), is 2.7x10-4L/(mol.s)
at 600K and 3.5x10-3L/(mol.s) at 650K. (1) Find the
activation energy(Ea). (2) Predict a k value at 670K.